ABS:Mm gff: Difference between revisions
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test | test | ||
$\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$ | $$\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$$ | ||
Revision as of 07:03, 8 May 2022
test
$$\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$$