ABS:Mm gff: Difference between revisions

Revision as of 07:06, 8 May 2022

test

$\sum _{i=0}^{n}i^{2}={\frac {(n^{2}+n)(2n+1)}{6}}$

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	<math>$$\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$$</math>		<math>\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}</math>